0.6x^2+2x-3=0

Solution for 0.6x^2+2x-3=0 equation:

0.6x^2+2x-3=0

a = 0.6; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·0.6·(-3)
Δ = 11.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{11.2}}{2*0.6}=\frac{-2-\sqrt{11.2}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{11.2}}{2*0.6}=\frac{-2+\sqrt{11.2}}{1.2}
$